3x^2-10x+22=2x^2

Solution for 3x^2-10x+22=2x^2 equation:

3x^2-10x+22=2x^2

We move all terms to the left:

3x^2-10x+22-(2x^2)=0

determiningTheFunctionDomain
3x^2-2x^2-10x+22=0

We add all the numbers together, and all the variables

x^2-10x+22=0

a = 1; b = -10; c = +22;
Δ = b2-4ac
Δ = -102-4·1·22
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{3}}{2*1}=\frac{10-2\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{3}}{2*1}=\frac{10+2\sqrt{3}}{2}
$